2小时之Python入门 - Doulorの小世界

哈哈哈哈，重生之我在VSCode被GPT教学Python，光速入门哈哈哈混了那么久的程序员这个圈子今天才刚开始学编程，下面直接放我2小时的最终成功，是GPT给我题目让我自己动手写的，题目如下：

🎯 练手题目：统计多种字符类型（函数版）

任务：

用户输入一句话

写四个函数：

count_vowels(text) → 返回元音数量

count_numbers(text) → 返回数字数量

count_spaces(text) → 返回空格数量

count_other_letters(text) → 返回除元音以外的字母数量

主程序里调用这四个函数，然后打印结果：

输入一句话：Hello World 123 元音字母数量：3 数字数量：3 空格数量：2 其他字母数量：7

要求：

每个函数用 for + if / elif / else 遍历和判断

每个函数必须用 return 返回结果

主程序只负责调用函数和打印结果

我的答案当然不是一次性写对的，被纠错了两次

最开始我就知道我错了，但是不知道怎么改，初稿如下

1
def count_yuanyin(text):
2
    yuanyins = ['a', 'e', 'i', 'o', 'u',]
3
    yuanyin = 0
4
    for ch in text:
5
        f ch in yuanyin:
6
            yuanyin += 1
7
    return yuanyin
8
def count_shuzi(text):
9
    shuzis = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
10
    shuzi = 0
11
    for ch in text:
12
        if ch in shuzis:
13
            shuzi += 1
14
    return shuzi
15
def count_kongge(text):
16
    kongges = [' ']
17
    kongge = 0
18
    for ch in text:
19
        if ch in kongges:
20
            kongge += 1
21
    return kongge
22
def count_other(text):
23
    other = 0
24
    for ch in text:
25
        if ch != shuzi and ch != yuanyin and ch !=kongge:
26
            other += 1
27
    return other
28
text = input("请输入一段文本：")
29
yuanyin = count_yuanyin(text)
30
shuzi = count_shuzi(text)
31
kongge = count_kongge(text)
32
other = count_other(text)
33
print("元音字母有", yuanyin , "个")
34
print("数字有", shuzi , "个")
35
print("空格有", kongge , "个")
36
print("其他字符有", other , "个")

虽然写错了但是感觉也差不多嘛

下面是最终答案

1
def count_yuanyin(text):
2
    yuanyins = ['a', 'e', 'i', 'o', 'u',]
3
    yuanyin = 0
4
    for ch in text:
5
        if ch in yuanyins:
6
            yuanyin += 1
7
    return yuanyin
8
def count_shuzi(text):
9
    shuzis = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
10
    shuzi = 0
11
    for ch in text:
12
        if ch in shuzis:
13
            shuzi += 1
14
    return shuzi
15
def count_kongge(text):
16
    kongges = [' ']
17
    kongge = 0
18
    for ch in text:
19
        if ch in kongges:
20
            kongge += 1
21
    return kongge
22
def count_other(text):
23
    shuzis = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
24
    yuanyins = ['a', 'e', 'i', 'o', 'u']
25
    kongges = [' ']
26
    other = 0
27
    for ch in text:
28
        if ch not in shuzis and ch not in yuanyins and ch not in kongges:
29
            other += 1
30
    return other
31
text = input("请输入一段文本：")
32
yuanyin = count_yuanyin(text)
33
shuzi = count_shuzi(text)
34
kongge = count_kongge(text)
35
other = count_other(text)
36
print("元音字母有", yuanyin , "个")
37
print("数字有", shuzi , "个")
38
print("空格有", kongge , "个")
39
print("其他字符有", other , "个")

感觉不错(╹ڡ╹ ) 好玩😋😋😋

DoulorのWorldlet